Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Cumulative Review Exercises - Page 660: 37

Answer

$y=-3x-1$

Work Step by Step

The equation of the line passing through the point $(-2,5)$ is: $$\begin{align*} y-5&=m(x-(-2))\\ y-5&=m(x+2). \end{align*}$$ In order to determine the slope $m$ we use the slope $m_1$ of the line $3x+y=9$. We determine the slope $m_1$: $$\begin{align*} 3x+y&=9\\ y&=-3x+9. \end{align*}$$ It means that $m_1=-3$. Since our line is parallel to the line of slope $m_1=-3$, it means they have the same slope: $$m=m_1=-3.$$ Now our line's equation is fully determined. We bring it to the slope-intercept: $$\begin{align*} y-5&=-3(x+2)\\ y&=-3x-6+5\\ y&=-3x-1. \end{align*}$$
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