Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Cumulative Review Exercises - Page 660: 28

Answer

$44+6i$.

Work Step by Step

Use the FOIL method to multiply $5+3i$ and $7-3i$. $(5+3i)(7-3i)$ $=5\cdot 7+5\cdot (-3i)+(3i)\cdot 7+(3i)\cdot (-3i)$ $=35-15i+21i-9i^2$ $=35+6i-9i^2$ Use $i^2=-1$. $=35+6i-9(-1)$ $=35+6i+9$ Simplify. $=44+6i$.
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