Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Cumulative Review Exercises - Page 660: 22

Answer

$9x^4-24x^2y+16y^2$.

Work Step by Step

Use the algebraic identity $(a-b)^2=a^2-2ab+b^2$ where $a=3x^2$ and $b=4y$. $(3x^2-4y)^2=(3x^2)^2-2(3x^2)(4y)+(4y)^2$ Clear the parentheses. $=3^2x^2-24x^2y+4^2y^2$ Simplify. $=9x^4-24x^2y+16y^2$.
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