Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Cumulative Review Exercises - Page 660: 30

Answer

$2x(3x-2)(4x-1)$.

Work Step by Step

An expression is factored completely if it is written as a product of factors so that none of its factors can be further factored. Factor out $2x$ from all terms of the given expression. $24x^3-22x^2+4x=2x(12x^2-11x+2)$ Rewrite the middle term $-11x$ of the quadratic factor as $-8x-3x$ $=2x(12x^2-8x-3x+2)$ Group the terms. $=2x[(12x^2-8x)+(-3x+2)]$ Factor each term. $=2x[4x(3x-2)-1(3x-2)]$ Factor out $(3x-2)$. $=2x(3x-2)(4x-1)$.
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