Answer
$2x(3x-2)(4x-1)$.
Work Step by Step
An expression is factored completely if it is written as a product of factors so that none of its factors can be further factored.
Factor out $2x$ from all terms of the given expression.
$24x^3-22x^2+4x=2x(12x^2-11x+2)$
Rewrite the middle term $-11x$ of the quadratic factor as $-8x-3x$
$=2x(12x^2-8x-3x+2)$
Group the terms.
$=2x[(12x^2-8x)+(-3x+2)]$
Factor each term.
$=2x[4x(3x-2)-1(3x-2)]$
Factor out $(3x-2)$.
$=2x(3x-2)(4x-1)$.