Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Cumulative Review Exercises - Page 660: 34

Answer

$2a+h+3$.

Work Step by Step

Plug $x=(a+h)$ into the function $f(x)$ to find $f(a+h)$. $f(a+h)=(a+h)^2+3(a+h)-15$ Simplify. $f(a+h)=a^2+2ah+h^2+3a+3h-15$ Plug $x=a$ into the function $f(x)$ to find $f(a)$. $f(a)=a^2+3a-15$. Substitute the expressions of $f(a+h)$ and $f(a)$ in the required expression. $\frac{f(a+h)-f(a)}{h}$ $=\frac{a^2+2ah+h^2+3a+3h-15-(a^2+3a-15)}{h}$ Simplify. $=\frac{a^2+2ah+h^2+3a+3h-15-a^2-3a+15}{h}$ $=\frac{2ah+h^2+3h}{h}$ $=\frac{h(2a+h+3)}{h}$ $=2a+h+3$.
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