Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 7



Work Step by Step

Given: $\dfrac{4x-2}{3}=2$ or, $4x-2=6 \implies x= 2$ Now, $\dfrac{4x-2}{3}=-2$ or, $4x-2=-6 \implies x=-1$ Hence, {$-1,2$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.