Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 19



Work Step by Step

Given: $7|5x|+2=16$ This can also be written as: $7|5x|=14$ or, $|5x|=2$ As per definition of absolute value, we have $5x=2$ and $5x=-2$ Thus, $x=\dfrac{2}{5}$ and $x=\dfrac{-2}{5}$ Hence, {$-\dfrac{2}{5},\dfrac{2}{5}$}
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