Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 28



Work Step by Step

Given: $4x-9=2x+1$ or, $4x-2x=1+9$ or, $2x=10 \implies x=5$ Now, $4x-9=-(2x+1)$ or, $4x+2x=-1+9$ or, $6x=8 \implies x=\dfrac{8}{6}=\dfrac{4}{3}$ Hence, {$\dfrac{4}{3},5$}
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