Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 34



Work Step by Step

Given: $x-3=6-x$ or, $ 2x-3=6$ or, $2x=6+3 \implies x=\dfrac{9}{2}$ Now, $x-3=-(6-x)$ or, $x-3=-6+x$ or, $-3 \neq -6$ Hence, {$\dfrac{9}{2}$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.