Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 20

{$-\dfrac{2}{3},\dfrac{2}{3}$}

Given: $7|3x|+2=16$ This can also be written as: $7|3x|=14$ or, $|3x|=2$ As per definition of absolute value, we have $3x=2$ and $3x=-2$ Thus, $x=\dfrac{2}{3}$ and $x=\dfrac{-2}{3}$ Hence, {$-\dfrac{2}{3},\dfrac{2}{3}$}