Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 50

Answer

$(-\infty,-3)\cup (7,\infty)$

Work Step by Step

We are asked to solve the absolute value inequality: $|x-2|\gt 5$ We remove the absolute value sign by splitting the inequality into two as follows: $x-2 \lt -5$ or $x-2 \gt 5$ Now, we solve for (isolate) $x$: $x-2+2 \lt -5+2$ or $x-2+2 \gt 5+2$ $x \lt -3$ or $x \gt 7$ In interval notation, this can be written as: $(-\infty,-3)\cup (7,\infty)$ See the number line graph below.
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