## Intermediate Algebra for College Students (7th Edition)

{$\dfrac{1}{2}$}
Given: $|2x-1|+3=3$ or, $|2x+1|=3-3$ or, $|2x+1|=0$ or, $2x-1=0$ This implies that the expression will have only one solution. Thus, $x=\dfrac{1}{2}$ Hence, {$\dfrac{1}{2}$}