Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 27



Work Step by Step

Given: $5x-8=3x+2$ or, $5x-3x=2+8$ or, $2x=10 \implies x=5$ Now, $5x-8=-(3x+2)$ or, $5x+3x=-2+8$ or, $8x=6 \implies x=\dfrac{6}{8}=\dfrac{3}{4}$ Hence, {$\dfrac{3}{4},5$}
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