## Intermediate Algebra for College Students (7th Edition)

$(3,\;1)$
For the first equation $x+y=4$, the $x$ and $y$ intercepts are found as $(4,0)$ and $(0,4)$ respectively by substituting 0 for $y$ and $x$ in equation. Similarly, for the second equation $x-y=2$, the $x$ and $y$ intercepts are found as $(2,0)$ and $(0,-2)$ respectively by substituting 0 for $y$ and $x$ in equation. So, graph each equation as a line passing through intercepts. Both graphs intersect at $(3,1)$. So, the solution is $(3,1)$. The graph obtained is as below.