Answer
Infinitely many solutions with $(x,y)|y=\dfrac{1}{3}x+4 $ or $(x,y)|3y=x+12$
Work Step by Step
To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable.
$3y=x+12$
Now, $3(1/3x+4)=x+12$
or, $x+12=x+12$
or, $12=12$
or, $0=0$
Hence, the given equation has Infinitely many solutions with $(x,y)|y=\dfrac{1}{3}x+4 $ or $(x,y)|3y=x+12$
