Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 190: 30

Answer

$(2,-2)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $2(3y+8)-y=6$ or, $5y+16=6$ or, $5y=-10$ or, $y=-2$ Now, $x=3y+8=3(-2)+8=2$ Hence, the desired result is: $(2,-2)$
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