## Intermediate Algebra for College Students (7th Edition)

$(2,-2)$
To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $2(3y+8)-y=6$ or, $5y+16=6$ or, $5y=-10$ or, $y=-2$ Now, $x=3y+8=3(-2)+8=2$ Hence, the desired result is: $(2,-2)$