Answer
Infinitely many solutions with $(x,y)|x=3y-1 $ or $(x,y)|2x-6y=-2$
Work Step by Step
To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable.
$2x-6y=-2 $ and $x=3y-1$
Now, $2(3y-1)-6y=-2 $
or, $6y-2=6y-2$
or, $6x=6xx$ or, $0=0$
Hence, the given equation has Infinitely many solutions with $(x,y)|x=3y-1 $ or $(x,y)|2x-6y=-2$