Answer
$(3,-1)$.
Work Step by Step
First equation $x+2y=1$.
Plug $y=0$ into the equation.
$\Rightarrow x+2(0)=1$
$\Rightarrow x=1$
$x−$ intercept $A=(1,0)$.
Plug $x=0$ into the equation.
$\Rightarrow (0)+2y=1$
$\Rightarrow 2y=1$
$\Rightarrow \frac{2y}{2}=\frac{1}{2}$
$\Rightarrow y=\frac{1}{2}$
$y−$ intercept $B=(0,\frac{1}{2})$.
Now for the second equation $x=3$.
This is in the form of the vertical line $x=k$. Where, $k$ is the $x-$intercept.
We have $x-$intercept $C=(3,0)$ and the other point is $(3,1)$.
Draw two lines using intercept points.
The intersection point of both lines is the solution.
Here we have the intersection point at $(3,-1)$.
