Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 190: 36

Answer

$(-2,1)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $2(6y-8)+5y=1$ or, $12y-16+5y=1$ or, $17y-16=1$ or, $y=1$ Now, $x=6y-8=6(1)-8=-2$ Hence, the desired result is: $(-2,1)$
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