Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 190: 32

Answer

$(-3,-2)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $3(3+3y)+5y=-19$ or, $14y+9=-19$ or, $14y=-28$ or, $y=-2$ Now, $x=3+3y=3+3(-2)=-3$ Hence, the desired result is: $(-3,-2)$
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