Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises: 9

Answer

$\frac{1}{2},\frac{8}{9},\frac{6}{5},\frac{16}{11},\frac{5}{3}$

Work Step by Step

$a_n=\frac{4n}{n+7}$ $a_1=\frac{4}{8}=\frac{1}{2}$ $a_2=\frac{4\times2}{2+7}=\frac{8}{9}$ $a_3=\frac{4\times3}{3+7}=\frac{12}{10}=\frac{6}{5}$ $a_4=\frac{4\times4}{4+7}=\frac{16}{11}$ $a_5=\frac{4\times5}{5+7}=\frac{20}{12}=\frac{5}{3}$
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