Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises - Page 727: 21



Work Step by Step

$a_n=\frac{2n}{n+8}$ when $a_n=1.2$ $\frac{2n}{n+8}=1.2$ $\implies 2n=1.2(n+8)$ $\implies 2n=1.2n+9.6$ $\implies 0.8n=9.6$ $\implies n=12$
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