## Intermediate Algebra: Connecting Concepts through Application

$-16.5$,-15,75,-14.625,-12.9375$,-10.4063$
$f(n)=1.5^n-18$ $f(1)=1.5^1-18=-16.5$ $f(2)=1.5^2-18=-15,75$ $f(3)=1.5^3-18=-14.625$ $f(4)=1.5^4-18=-12.9375$ $f(5)=1.5^5-18=-10.4063$