Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises - Page 727: 12



Work Step by Step

$a_n=\frac{2}{3^n}$ $a_1=\frac{2}{3^1}=\frac{2}{3}$ $a_2=\frac{2}{3^2}=\frac{2}{9}$ $a_3=\frac{2}{3^3}=\frac{2}{27}$ $a_4=\frac{2}{3^4}=\frac{2}{81}$ $a_5=\frac{2}{3^5}=\frac{2}{243}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.