Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises: 12

Answer

$\frac{2}{3},\frac{2}{9},\frac{2}{27},\frac{2}{81},\frac{2}{243}$

Work Step by Step

$a_n=\frac{2}{3^n}$ $a_1=\frac{2}{3^1}=\frac{2}{3}$ $a_2=\frac{2}{3^2}=\frac{2}{9}$ $a_3=\frac{2}{3^3}=\frac{2}{27}$ $a_4=\frac{2}{3^4}=\frac{2}{81}$ $a_5=\frac{2}{3^5}=\frac{2}{243}$
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