#### Answer

$\frac{3}{14},\frac{6}{13},\frac{3}{4},\frac{12}{11},\frac{3}{2}$

#### Work Step by Step

$a_n=\frac{-3n}{n-15}$
$a_1=\frac{-3}{-14}=\frac{3}{14}$
$a_2=\frac{-3\times2}{2-15}=\frac{-6}{-13}=\frac{6}{13}$
$a_3=\frac{-3\times3}{3-15}=\frac{-9}{-12}=\frac{3}{4}$
$a_4=\frac{-3\times4}{4-15}=\frac{-12}{-11}=\frac{12}{11}$
$a_5=\frac{-3\times5}{5-15}=\frac{-15}{-10}=\frac{3}{2}$