Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises: 4

Answer

$6,12,24,48$

Work Step by Step

$f(n)=3(2^n)$ $f(1)=3\times2^1=6$ $f(2)=3\times2^2=12$ $f(3)=3\times2^3=24$ $f(4)=3\times2^4=48$
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