Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises: 18

Answer

$n=33$

Work Step by Step

$a_n=-5n^2+40$ when $a_n=-5405$ $-5n^2+40=-5405$ $\implies -5n^2=-5445$ $\implies n^2=1089$ $\implies n=\sqrt{1089}=33$
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