Answer
$= 5a^{2}b+6ab^{2}-7b$
Work Step by Step
$\frac{10a^{3}b^{2}+12a^{2}b^{3}-14ab^{2}}{2ab}$
$=\frac{2ab(5a^{2}b+6ab^{2}-7b)}{2ab}$
$=\frac{5a^{2}b+6ab^{2}-7b}{1}$
$= 5a^{2}b+6ab^{2}-7b$
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