Answer
$= \frac{-(4x-3)}{(5x+1)}$
Work Step by Step
$\frac{(4x-3)(7-2x)}{(2x-7)(5x+1)}$
$= \frac{(4x-3)(-(2x-7))}{(2x-7)(5x+1)}$
$= \frac{-(4x-3)}{(5x+1)}$
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