Answer
$= \frac{(w-4)}{(w-3)}$
Work Step by Step
$\frac{w^{2}-16}{w^{2}+w-12}$
$= \frac{(w+4)(w-4)}{w^{2}+w-12}$
$= \frac{(w+4)(w-4)}{w^{2}+4w-3w-12}$
$= \frac{(w+4)(w-4)}{w(w+4)-3(w+4)}$
$= \frac{(w+4)(w-4)}{(w-3)(w+4)}$
$= \frac{(w-4)}{(w-3)}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 7 - Rational Functions - 7.2 Simplifying Rational Expressions - 7.2 Exercises - Page 575: 19
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