Answer
$=\frac{(t-1)}{(t-8)}$
Work Step by Step
$\frac{t^{2}+7t-8}{t^{2}-64}$
$=\frac{t^{2}+7t-8}{(t-8)(t+8)}$
$=\frac{t^{2}+8t-t-8}{(t-8)(t+8)}$
$=\frac{t(t+8)-1(t+8)}{(t-8)(t+8)}$
$=\frac{(t-1)(t+8)}{(t-8)(t+8)}$
$=\frac{(t-1)}{(t-8)}$
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