Answer
$= \frac{(x+7)}{(x-4)}$
Work Step by Step
$\frac{x^{2}+5x-14}{x^{2}-6x+8}$
$= \frac{x^{2}+7x-2x-14}{x^{2}-4x-2x+8}$
$= \frac{x(x+7)-2(x+7)}{x(x-4)-2(x-4)}$
$= \frac{(x-2)(x+7)}{(x-2)(x-4)}$
$= \frac{(x+7)}{(x-4)}$
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