Answer
$= \frac{(2x+5)}{(x-7)}$
Work Step by Step
$\frac{2x^{2}-23x-70}{x^{2}-21x+98}$
$= \frac{2x^{2}-23x-70}{x^{2}-21x+98}$
$= \frac{2x^{2}-28x+5x-70}{x^{2}-14x-7x+98}$
$= \frac{2x(x-14)+5(x-14)}{x(x-14)-7(x-14)}$
$= \frac{(2x+5)(x-14)}{(x-7)(x-14)}$
$= \frac{(2x+5)}{(x-7)}$