Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.2 Simplifying Rational Expressions - 7.2 Exercises - Page 575: 25

Answer

$= \frac{(2x+5)}{(x-7)}$

Work Step by Step

$\frac{2x^{2}-23x-70}{x^{2}-21x+98}$ $= \frac{2x^{2}-23x-70}{x^{2}-21x+98}$ $= \frac{2x^{2}-28x+5x-70}{x^{2}-14x-7x+98}$ $= \frac{2x(x-14)+5(x-14)}{x(x-14)-7(x-14)}$ $= \frac{(2x+5)(x-14)}{(x-7)(x-14)}$ $= \frac{(2x+5)}{(x-7)}$
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