Answer
$7+0i$
Work Step by Step
$(\sqrt 3+2i)(\sqrt 3-2i)$
=$\sqrt 3(\sqrt 3-2i)+2i(\sqrt 3-2i)$
=$\sqrt 3\sqrt 3-2i\sqrt 3+2i\sqrt 3-4i^{2}$
=$\sqrt 3\sqrt 3-4i^{2}$
=$(\sqrt 3)^{2}-4i^{2}$
=$3-4(-1)$
=$7$
=$7+0i$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Cumulative Review - Page 534: 46c
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