Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 41b

Answer

$\frac{8\sqrt {x}}{3x}$

Work Step by Step

$\frac{2\sqrt {16}}{\sqrt {9x}}\times\frac{\sqrt {9x}}{\sqrt {9x}}$ =$\frac{2\sqrt {16}\times\sqrt {9x}}{\sqrt {9x}\times\sqrt {9x}}$ =$\frac{2(4)\times 3\sqrt {x}}{3\sqrt {x}\times 3\sqrt {x}}$ =$\frac{8\times 3\sqrt {x}}{9x}$ =$\frac{8\times \sqrt {x}}{3x}$ =$\frac{8\sqrt {x}}{3x}$
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