Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 42a

Answer

$-2-6\sqrt 3$

Work Step by Step

$(\sqrt 3-4)(2\sqrt 3+2)$ =$\sqrt 3(2\sqrt 3+2)-4(2\sqrt 3+2)$ =$2\sqrt 3\sqrt 3+2\sqrt 3-4(2\sqrt 3)-8$ =$2(3)+2\sqrt 3-8\sqrt 3-8$ =$6+2\sqrt 3-8\sqrt 3-8$ =$6-8+(2-8)\sqrt 3$ =$-2-6\sqrt 3$
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