Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 14

Answer

$2a(x-3y)^{2}$

Work Step by Step

$2ax^{2}-12axy+18ay^{2}$ =$2ax^{2}-6axy-6axy+18ay^{2}$ =$2ax(x-3y)-6ay(x-3y)$ =$(x-3y)(2ax-6ay)$ =$(2ax-6ay)\times(x-3y)$ =$2a(x-3y)\times(x-3y)$ =$2a(x-3y)(x-3y)$ =$2a(x-3y)^{2}$
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