Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 40a

Answer

$8a^{2}\sqrt a$

Work Step by Step

$\sqrt {64a^{5}}$ =$\sqrt {8^{2}\times a^{4}\times a}$ =$\sqrt {8^{2}}\times \sqrt {a^{4}}\times \sqrt a$ =$8\times a^{2}\times \sqrt a$ =$8a^{2}\sqrt a$
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