Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 37c

Answer

$\sqrt {rs^{3}}$

Work Step by Step

$\sqrt[4] {r^{2}s^{6}}=(r^{2}s^{6})^{\frac{1}{4}}=(r^{2})^{\frac{1}{4}}(s^{6})^{\frac{1}{4}}=(r)^{\frac{1}{2}}(s^{3})^{\frac{1}{2}}=\sqrt {rs^{3}}$
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