Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 36a



Work Step by Step

$\sqrt {(-2)^{2}}$ =$(-2)^{2\times\frac{1}{2}}$ =$(-2)^{1}$ =$-2$
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