Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 42



Work Step by Step

Raising both sides to the third power of the given equation, $ \sqrt[3]{-4x-3}=\sqrt[3]{-x-15} ,$ then the solution/s is/are \begin{array}{l}\require{cancel} -4x-3=-x-15 \\\\ -4x+x=-15+3 \\\\ -3x=-12 \\\\ x=\dfrac{-12}{-3} \\\\ x=4 .\end{array}
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