Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set - Page 453: 35

Answer

$x=-12$

Work Step by Step

Using the properties of equality, the given equation, $ \sqrt[3]{2x-3}-2=-5 ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt[3]{2x-3}=-5+2 \\\\ \sqrt[3]{2x-3}=-3 .\end{array} Raising both sides of the equation above to the third power, then the solution/s is/are \begin{array}{l}\require{cancel} 2x-3=-27 \\\\ 2x=-27+3 \\\\ 2x=-24 \\\\ x=-\dfrac{24}{2} \\\\ x=-12 .\end{array}
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