Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 34

Answer

$x=9$

Work Step by Step

Using the properties of equality, the given equation, $ \sqrt[3]{3x}+4=7 ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt[3]{3x}=7-4 \\\\ \sqrt[3]{3x}=3 .\end{array} Raising both sides of the equation above to the third power, then the solution/s is/are \begin{array}{l}\require{cancel} 3x=27 \\\\ x=\dfrac{27}{3} \\\\ x=9 .\end{array}
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