Answer
$x=5$
Work Step by Step
Using the properties of equality, the given equation, $
\sqrt[3]{6x-3}-3=0
,$ is equivalent to
\begin{array}{l}\require{cancel}
\sqrt[3]{6x-3}=3
.\end{array}
Raising both sides of the equation above to the third power, then the solution/s is/are
\begin{array}{l}\require{cancel}
6x-3=27
\\\\
6x=27+3
\\\\
6x=30
\\\\
x=\dfrac{30}{6}
\\\\
x=5
.\end{array}