Answer
$x=-\frac{9}{2}$
Work Step by Step
$\sqrt[3] (6x)=-3$
Cube both sides of the equation.
$(\sqrt[3] (6x))^{3}=(-3)^{3}$
$6x=-27$
Divide both sides by 6.
$x=-\frac{27}{6}=-\frac{9}{2}$
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