## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 32

#### Answer

$x=9$

#### Work Step by Step

Squaring both sides of the given equation, $\sqrt{3x+9}=6 ,$ then the solution/s is/are \begin{array}{l}\require{cancel} 3x+9=36 \\\\ 3x=36-9 \\\\ 3x=27 \\\\ x=\dfrac{27}{3} \\\\ x=9 .\end{array} Upon checking, $x=9$ satisfies the original equation.

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