## Intermediate Algebra (6th Edition)

$$x=181/36$$
We solve: $$\sqrt{x+3}=(3- \sqrt{x-5})$$ We now square both sides: $$(\sqrt{x+3})^2=(3- \sqrt{x-5})^2$$ $${x+3}=(9- 6\sqrt{x-5})+x-5$$ $${-1}=(6\sqrt{x-5})$$ $${-1/6}=(\sqrt{x-5})$$ $${1/36}=({x-5})$$ $$x=181/36$$