## Intermediate Algebra (6th Edition)

$x=9$
Squaring both sides of the given equation, $\sqrt{x+4}=\sqrt{2x-5} ,$ then the solution/s is/are \begin{array}{l}\require{cancel} x+4=2x-5 \\\\ x-2x=-5-4 \\\\ -x=-9 \\\\ x=9 .\end{array} Upon checking, $x=9$ satisfies the original equation.