Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 151

Answer

$\dfrac{n\sqrt{3n}}{11m^5}$

Work Step by Step

Using properties of radicals, the expression $ \sqrt{\dfrac{3n^3}{121m^{10}}} $ simplifies to \begin{array}{l} \sqrt{\dfrac{n^2}{121m^{10}}\cdot3n} \\\\= \dfrac{n}{11m^5}\cdot\sqrt{3n} \\\\= \dfrac{n\sqrt{3n}}{11m^5} .\end{array}
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