## Intermediate Algebra (6th Edition)

$\sqrt{241} \text{ } ft$
Using $a^2+b^2=c^2$ (or the Pythagorean Theorem) with legs having measures $7$ and $8\sqrt{3}$, then the hypotenuse, $c$, is \begin{array}{l}\require{cancel} 7^2+(8\sqrt{3})^2=c^2 \\\\ 49+64\cdot3=c^2 \\\\ 49+192=c^2 \\\\ 241=c^2 \\\\ c=\sqrt{241} .\end{array} Hence the hypotenuse is $\sqrt{241} \text{ } ft .$